Two bags A and B contain different colours of balls In bag A there are 2 red balls 3 green balls and...........

Quantitative Aptitude(IBPS PO) Probability

Two bags A and B contain different colours of balls. In bag A, there are 2 red balls, 3 green balls and 5 white balls while bag B contain 4 red balls, ‘x’ green balls and 3 white balls. If the probability of drawing one white ball from bag A is 1/6 more than the probability of drawing one red ball from bag B, then find the value of ‘x’.

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Explanation:

In bag A,
Number of red, green and white balls is 2, 3 and 5 respectively.
Total number of balls in bag A = 10
So, probability of drawing one white ball from bag A = 5/10
In bag B,
Number of green balls is x
Total number of balls in bag B = x + 7
So, probability of drawing one red ball from bag B = 4/(x+7)
Given that,
5/10 - 4/(x+7) = 1/6
4/(x+7) = 5/10-1/6
4/(x+7) = 1/2-1/6
4/(x+7) = 1/3
x+7 = 12
x=5