For position D if respective ratio of accepted amp rejected applications is 4 1 Which of the followi...........

Quantitative Aptitude(IBPS PO) Data Table

Directions (): Read the data carefully and answer the questions. Some data are missing which you have to calculate as per information provided in the questions.

NOTE:- A duplicate applicant is an applicant who has submitted additional (duplicate) application after submitting their original application. All application forms (original + duplicate) received from duplicate applicant were rejected. Remaining all application were accepted. None of the applicants applied for more than one post.

For position D, if respective ratio of accepted & rejected applications is 4 : 1. Which of the following can be true? (average number of duplicate applications received for D is a non – zero integer)

A. no. of applications received for D (all original + all duplicate) can be 240.

B. no. of applications accepted for D can be 768.

C. least no. of applications (all original + all duplicate) were received for D is a possibility.

only B & C

none of the option

only C

only A & C

only B

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Explanation:

All applicants who submitted more than one application, their original submission is also rejected.
FOR POSITION A:
63 applications were declared duplicate since these 63 applicants submitted more than one application
Total rejected applications = 63+63×4=315
Following the same, we get

Where, p = no. of duplicate applicants for B
q = average no. of duplicate applications from duplicate applicants for C
r = average no. of duplicate applications from duplicate applicants for D
s = total no. of applications received for D
t = no. of duplicate applicants for E
u = average no. of duplicate applications from duplicate applicants for E

A. Given s = 240
This is possible only when r = 0 but we know r > 0 (average no. of duplicate applications from duplicate applicants cannot be zero since there are applications which were declared duplicate)
This condition is not true.
B. Given s – 48(r + 1) = 768
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From (i), 240(r + 1) – 48(r + 1) = 768
192 (r + 1) = 768 ⇒ r = 3
this condition is true.
C. least no. of applications were received for D is a possibility. This is true only if s < 420 (since 420 applications were received for E)
240 (r + 1) < 420
r + 1 < 1.75 ⇒ r < 0.75
this is not possible as we know r can only be non – zero integer
so, this condition is not true.