If average no of accepted applications for position A amp B is 659 What is the value of rejected app...........

Quantitative Aptitude(IBPS PO) Data Table

Directions (): Read the data carefully and answer the questions. Some data are missing which you have to calculate as per information provided in the questions.

NOTE:- A duplicate applicant is an applicant who has submitted additional (duplicate) application after submitting their original application. All application forms (original + duplicate) received from duplicate applicant were rejected. Remaining all application were accepted. None of the applicants applied for more than one post.

If average no. of accepted applications for position A & B is 659. What is the value of rejected applications for position B?

287

246

254

275

263

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Explanation:

All applicants who submitted more than one application, their original submission is also rejected.
FOR POSITION A:
63 applications were declared duplicate since these 63 applicants submitted more than one application
Total rejected applications = 63+63×4=315
Following the same, we get

Where, p = no. of duplicate applicants for B
q = average no. of duplicate applications from duplicate applicants for C
r = average no. of duplicate applications from duplicate applicants for D
s = total no. of applications received for D
t = no. of duplicate applicants for E
u = average no. of duplicate applications from duplicate applicants for E

ATQ, 725 + 880 – 7p = 659×2
Solving, p = 41
Required rejected applications = 7p = 287