For position E no of accepted applications from males from females amp no of rejected applications t...........

Quantitative Aptitude(IBPS PO) Data Table

Directions (): Read the data carefully and answer the questions. Some data are missing which you have to calculate as per information provided in the questions.

NOTE:- A duplicate applicant is an applicant who has submitted additional (duplicate) application after submitting their original application. All application forms (original + duplicate) received from duplicate applicant were rejected. Remaining all application were accepted. None of the applicants applied for more than one post.

For position E, no. of accepted applications from males, from females & no. of rejected applications (total) are X, X + Y, X + 2Y respectively. Which of the following is true? (average no. of duplicate applications received from duplicate applicant is non-zero integer)

A. no. of accepted applications from males for E can be 139.

B. no. of accepted applications from males for E can be 141.

C. no. of accepted applications from males for E can be 131.

A & B

A & C

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Explanation:

All applicants who submitted more than one application, their original submission is also rejected.
FOR POSITION A:
63 applications were declared duplicate since these 63 applicants submitted more than one application
Total rejected applications = 63+63×4=315
Following the same, we get

Where, p = no. of duplicate applicants for B
q = average no. of duplicate applications from duplicate applicants for C
r = average no. of duplicate applications from duplicate applicants for D
s = total no. of applications received for D
t = no. of duplicate applicants for E
u = average no. of duplicate applications from duplicate applicants for E

ATQ, 420 – t(u + 1) = X + X + Y ……………….(i)
t(u + 1) = X + 2Y …………………(ii)
using (i) & (ii)
420 = 3 (X + Y)
X + Y = 140 …………….(iii)
A. X = 139
This means, Y = 1
Since no relation regarding value of Y is given so, this is possible.
Given condition is true.
B. X = 141
Using (iii), X at most can be 140
This condition is not possible
C. X = 131
This means, Y = 9
Since no relation regarding value of Y is given so, this is possible.
Given condition is true.