For position A if respective ratio between no of accepted application from males amp that of rejecte...........

Quantitative Aptitude(IBPS PO) Data Table

Directions (): Read the data carefully and answer the questions. Some data are missing which you have to calculate as per information provided in the questions.

NOTE:- A duplicate applicant is an applicant who has submitted additional (duplicate) application after submitting their original application. All application forms (original + duplicate) received from duplicate applicant were rejected. Remaining all application were accepted. None of the applicants applied for more than one post.

For position A, if respective ratio between no. of accepted application from males & that of rejected applications from males is 5 : 3 & respective ratio of no. of accepted applications from females and that of rejected applications from females is 5 : 1 then find rejected applications from males.

230

315

425

255

300

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Explanation:

All applicants who submitted more than one application, their original submission is also rejected.
FOR POSITION A:
63 applications were declared duplicate since these 63 applicants submitted more than one application
Total rejected applications = 63+63×4=315
Following the same, we get

Where, p = no. of duplicate applicants for B
q = average no. of duplicate applications from duplicate applicants for C
r = average no. of duplicate applications from duplicate applicants for D
s = total no. of applications received for D
t = no. of duplicate applicants for E
u = average no. of duplicate applications from duplicate applicants for E

let accepted & rejected application from males is 5x & 3x respectively
Let accepted & rejected application from females is 5y & y respectively
5x + 5y = 725 ………………(i)
3x + y = 315 ……………….(ii)
Equating (i) & (ii)
x = 85
required no. of rejected applications from males = 3x = 255