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Direction (): Read the data given below carefully and answer the questions. A train running between four stations i.e. A, B, C & D on Monday and Tuesday. The average speed of train on Monday during whole journey is 50 kmph and average speed of train on Tuesday during whole journey is 62.5 kmph. On Monday train takes one hour less to cover distance between A and B as compare to that of on Tuesday. Train takes equal time to cover distance between B to C on both the given days, while train takes three hours more to cover distance between C and D as compare to that of on Tuesday. The distance between A and B is 40% less than that of between C and D. The distance between B and C is 50% more than that of between A and B. Note - There is not any halt or stoppage from the station A to D.
Find the total time taken by train to cover distance from A to D on Tuesday?
6 hours
8 hours
10 hours
12 hours
4 hours
Given average speed of train on Monday during whole journey = 50 kmph Or, Average speed of train on Tuesday during whole journey = 62.5 kmph = 125/2 km/h Let time taken by train on Monday from A to B = t hours So, time taken by train on Tuesday from A to B = (t + 1) hours Time taken by train on each given day from B to C = u hours (given, train takes equal time to cover distance between B to C on both the given days) And, time taken by train on Monday from C to D = v hours Time taken by train on Tuesday from C to D = (v – 3) hours Let distance between C to D = 100x km
From above explanation From (i) put the value of (t + u + v) and we get – (t +u + v −2) = 5x − 2 Total required time by train to cover distance from A to D on Tuesday = (5x – 2) = (5 ×2−2)=8 hours
By: Munesh Kumari ProfileResourcesReport error
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