On Monday speed of train between stations B to C is 50 more than speed of train between C to D and t...........

Data Interpretation ( IBPS PO) Case Studies

Direction (): Read the data given below carefully and answer the questions.
A train running between four stations i.e. A, B, C & D on Monday and Tuesday. The average speed of train on Monday during whole journey is 50 kmph and average speed of train on Tuesday during whole journey is 62.5 kmph. On Monday train takes one hour less to cover distance between A and B as compare to that of on Tuesday. Train takes equal time to cover distance between B to C on both the given days, while train takes three hours more to cover distance between C and D as compare to that of on Tuesday. The distance between A and B is 40% less than that of between C and D. The distance between B and C is 50% more than that of between A and B.
Note - There is not any halt or stoppage from the station A to D.

On Monday speed of train between stations B to C is 50% more than speed of train between C to D and time taken to cover distance between B to C is 2 hours less than that of time taken between C and D. Find the speed of train between C to D on Monday?

20 kmph

60 kmph

30 kmph

50 kmph

40 kmph

छोटे Courses बड़े Results

Master Case Studies

Prepare through Micro-courses

Try Now

Explanation:

Given average speed of train on Monday during whole journey = 50 kmph
Or, Average speed of train on Tuesday during whole journey = 62.5 kmph = 125/2 km/h
Let time taken by train on Monday from A to B = t hours
So, time taken by train on Tuesday from A to B = (t + 1) hours
Time taken by train on each given day from B to C = u hours (given, train takes equal time to cover distance between B to C on both the given days)
And, time taken by train on Monday from C to D = v hours
Time taken by train on Tuesday from C to D = (v – 3) hours
Let distance between C to D = 100x km
So, distance between A to B = 100x ×(100−40)/100 = 60x km
And distance between B to C = 60x ×150/100=90x km
For Monday, distance(AB+BC+CD)/time
For Monday, (100x +60x +90x)/(t+u+v)=50
So, t + u + v = 5x -------- (i)
For Tuesday, (100x +60x +90x)/(t+u+v-2)=125/2
From (i) put the value of (t + u + v) and we get –
250x/(5x−2)=125/2
x = 2
Now, distance between C to D = 100 ×2=200 km
Distance between A to B = 60 ×2=120 km
And, distance between B to C = 90 ×2=180 km