I 3x sup2 23x 42 0 II y sup2 ndash 42y 437 0 ........

Quantitative Aptitude(IBPS PO) Quadratic Equations

Direction: In the following question two equations are given in variables X and Y. You have to solve these equations and determine relation between X and Y.

I. 3x² + 23x + 42 = 0

II. y² – 42y + 437 = 0

X > Y

X < Y

X ≥ Y

X ≤ Y

X=Y or No relation can be established

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Explanation:

I. 3x²+23x+42=0
3x²+14x+9x+42=0
x(3x+14)+3(3x+14)=0
(x+3)(3x+14)=0
X=-3,
II. y²-42y+437=0
y²-19y-23y+437=0
y(y-19)-23(y-19)=0
(y-23)(y-19)-0
Y=23,19
Hence, option B is correct.