Multiple Choice Questions on The age of the mother 4 years ago was 6 times the age of her son at that time The age of the mother ........... for IBPS(Clerical) Exam Preparation

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Quantitative Aptitude(IBPS CL)

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    The age of the mother 4 years ago was 6 times the age of her son at that time. The age of the mother after 6 years will be 8/3 times the age of the son at the time. Find the difference between the mother's age after 2 years and the present age of the son.

    2 : 3

    Incorrect Answer

    3 : 2

    Incorrect Answer

    4 : 1

    Correct Answer

    5 : 2

    Incorrect Answer

    6 : 5

    Incorrect Answer
    Explanation:

    Let's break down the statements in the problem:

    - Let the present age of the mother be M and the son be S.

    - 4 years ago: Mother's age = M-4, Son's age = S-4

    Given: M - 4 = 6(S - 4)

    - 6 years from now: Mother's age = M+6, Son's age = S+6

    Given: M + 6 = (8/3)(S + 6)

    Let's solve the equations:

    1. M - 4 = 6S - 24 ? M = 6S - 20

    2. M + 6 = (8/3)S + 16

    So, M = (8/3)S + 10

    Set both expressions for M equal:

    6S - 20 = (8/3)S + 10

    6S - (8/3)S = 30

    (18S - 8S)/3 = 30

    10S = 90

    S = 9

    Plug into M:

    M = 6S - 20 = 6(9) - 20 = 54 - 20 = 34

    Mother's age after 2 years: 34 + 2 = 36

    Present age of son: 9

    Difference: 36 - 9 = 27

    Now, check the options:

    None of the options match 27!

    But if they mean ordered pairs "mother's age after 2 years : son's present age":

    36 : 9 simplifies to 4 : 1

    So, the correct answer is Option 3 - 4 : 1

    ---

    - If you substitute and solve, ages are: Mother 34, Son 9.

    - After 2 years, mother will be 36; son is 9 now.

    - Their ratio is 36:9, which reduces to 4:1.

    - Option 3 matches this result: 4 : 1.

    - Other options do not fit the values derived from the equations.


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