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The present age of mother is 42 years. After 12 years the ratio of ages of father and mother is 10:9 and the ratio of the present ages of their son and daughter is 5:6. Fathers present age is four times the present age of daughter. Find the sum of the ages of son and daughter after 12 years.
42 years
46 years
45 years
48 years
38 years
Here is the breakdown of the problem:
- Present Age of Mother: 42 years.
- After 12 Years, mother's age will be 54 years (42 + 12).
- Father's Age After 12 Years: Let it be \( F + 12 \).
- Given Ratio after 12 years: (Father's Age) : (Mother's Age) = 10 : 9.
Thus, $$(F + 12) / 54 = 10 / 9$$. Solving gives:
$$F + 12 = 60$$. Therefore, \( F = 48 \).
- Father's Present Age: 48 years.
- Father's Age Relation: Father’s age is four times daughter's age.
Hence, daughter's present age is \( 48 / 4 = 12 \).
- Son and Daughter's Present Age Ratio: 5 : 6.
$$(Son's Age) / 12 = 5 / 6$$. Solving gives:
Son's age = 10 years.
- Sum of Son and Daughter's Ages after 12 Years:
Son's age + 12 = 22 years,
Daughter's age + 12 = 24 years,
Sum = 22 + 24 = 46 years.
Therefore, the sum of the ages of the son and daughter after 12 years is 46 years.
Option: 2, 46 years
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By: Parvesh Mehta ProfileResourcesReport error
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