Explanation:

Let’s break down the clues step by step—here’s what we know:

- College B has 760 students, with 300 in Mechanical Engineering.

- Mechanical in B (300) is 60% of Mechanical in A, so Mechanical in A = 300 / 0.6 = 500.

- Electrical in A is 50% more than Electrical in B. Let’s call Electrical in B = x, then Electrical in A = x + 0.5x = 1.5x.

- In college C, Electrical is twice the Mechanical in the same college. Let’s say Mechanical in C = y, so Electrical in C = 2y.

- Civil in A is half its Mechanical = 0.5 × 500 = 250.

- Civil in A is also 50 more than Electrical in C: Civil in A = Electrical in C + 50 ? 250 = 2y + 50 ? y = 100.

- So, Mechanical in C = 100 and Electrical in C = 200.

- Total Civil students in all colleges = 750. We have Civil in A = 250, so Civil in B + Civil in C = 500.

- Civil in B = Electrical in C + 160 = 200 + 160 = 360.

- Civil in C = 750 - 250 (A) - 360 (B) = 140.

Now, recap the key numbers:

- Civil in A: 250

- Electrical in C: 200

So, the ratio is 250:200 or 5:4.

Let’s check the options:

- 2:3

- 4:7

- 4:5

- 5:3

- None of these

None of the options say 5:4—that’s your confirmation.

Correct Answer: Option 5 (None of these)

A quick summary of the important clues:

- Mechanical B given; find Mechanical A with 60%.

- Mechanical C is y = 100 from other clues.

- Electrical C = 2×y = 200; used to set Civil A and Civil B.

- All total checks work.

- The final ratio (Civil A : Electrical C) is 250:200 = 5:4.

So, “None of these” is right. Nice job!