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Directions (): Read the data carefully and answer the questions. There are 3 colleges A, B, C offering 3 courses mechanical engineering (ME), chemical engineering (CE) & electrical engineering (EE). College A: Number of students in ME is 40 less than that of in EE and number of students in CE is 50% more than that of in ME. College B: Number of students in EE is 20 less than that of in EE in college A. Number of students in CE is 340 which is 40 more than that of in CE in college A. Number of students in EE is 22(2/9)% more than that of in ME. College C: Number of students in ME is 40% less than that of in ME in college A. Number of students in CE is 40 less than that of in ME. Total students in EE in all colleges together are 780.
If 10% students of ME course from college A shifted to CE course in college C, then what is the difference between total number of students in CE in college C now and average of students in ME in all colleges now?
60
380
260
80
180
students who shifted to CE in college C from ME in college A = 20 Students in CE in college C now = 80+20 = 100 Average of students in ME of all colleges = (180 + 180 + 120)/3 = 160 Required difference = 160−100=60
By: Munesh Kumari ProfileResourcesReport error
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