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Direction: Study the following information carefully and answer the questions that follow. There are three different Guns A, B and C. Different numbers of bullets are fired from each Gun. A few of them hit the target while others missed. Gun A: 70% of the total number of fired bullets missed the target. Gun B: Total 900 bullets were fired and 33.33% hit the target. Gun C: 450 bullets hit the target. The number of bullets that hit the target by Gun A is 20% less than that by Gun B . The number of bullets that missed the target by Gun C is 6.25% less than the number of bullets fired by Gun A. Time gap between the firing of two bullets is 5 seconds, 3 seconds and 7 seconds for Gun A, Gun B and Gun C respectively.
Number of bullets fired by Gun A in 10 minutes is approximately how much percentage more than the number of bullets fired by Gun B in 4 minutes?
30%
45%
49%
64%
60%
Gun B: Total number of bullets fired = 900 Number of bullets that hit the target = 900 × 33.33% = 300 Number of bullets that missed the target = 900 – 300 = 600 Gun A: Number of bullets that hit the target = 300 × 80% = 240 Total number of bullets fired =240/30 x 100 = 800 Number of bullets missed the target = 800 – 240 = 560 Gun C: Number of bullets missed the target = 800 × (100 – 6.25)% = 750 Number of bullets hit the target = 450 Total number of bullets fired = 750 + 450 = 1200
Using the previous concept of number of terms in Arithmetic progression. Number of bullets fired by Gun A in 10 minutes =(10x 60)/5 + 1 = 121 Number of bullets fired by Gun A in 10 minutes =(4x60)/3 + 1 = 81 Difference = 121 – 81 = 40
Required percentage = 40/81 x 100 ≈ 49% Hence, option C is correct.
By: Munesh Kumari ProfileResourcesReport error
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