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Direction: Study the following information carefully and answer the questions that follow. There are three different Guns A, B and C. Different numbers of bullets are fired from each Gun. A few of them hit the target while others missed. Gun A: 70% of the total number of fired bullets missed the target. Gun B: Total 900 bullets were fired and 33.33% hit the target. Gun C: 450 bullets hit the target. The number of bullets that hit the target by Gun A is 20% less than that by Gun B . The number of bullets that missed the target by Gun C is 6.25% less than the number of bullets fired by Gun A. Time gap between the firing of two bullets is 5 seconds, 3 seconds and 7 seconds for Gun A, Gun B and Gun C respectively.
If all the Guns started firing at 12.00 pm, how many total bullets would be left to be fired by the 3 guns after 30 minutes? (It is known that none of the guns fired any time before 12:00 pm).
1683
1720
1672
1540
None of these
Gun B: Total number of bullets fired = 900 Number of bullets that hit the target = 900 × 33.33% = 300 Number of bullets that missed the target = 900 – 300 = 600 Gun A: Number of bullets that hit the target = 300 × 80% = 240 Total number of bullets fired =240/30 x 100 = 800 Number of bullets missed the target = 800 – 240 = 560 Gun C: Number of bullets missed the target = 800 × (100 – 6.25)% = 750 Number of bullets hit the target = 450 Total number of bullets fired = 750 + 450 = 1200
Using the previous concept of number of terms in Arithmetic progression. Number of bullets fired by Gun A in 30 minutes = (30x60)/5 + 1 = 361 ( here ⌊x⌋ is the greatest integer function) Number of bullets fired by Gun B in 30 minutes =(30x60)/3 + 1 = 601 Number of bullets fired by Gun C in 30 minutes =(30x60)/7 + 1 = 258 Remaining number of bullets in all Guns = (800 + 900 + 1200) – (361 + 601 + 258) = 1680 Hence, option E is correct.
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