Direction: Study the following information carefully and answer the questions that follow.
There are three different Guns A, B and C. Different numbers of bullets are fired from each Gun. A few of them hit the target while others missed.
Gun A: 70% of the total number of fired bullets missed the target.
Gun B: Total 900 bullets were fired and 33.33% hit the target.
Gun C: 450 bullets hit the target.
The number of bullets that hit the target by Gun A is 20% less than that by Gun B . The number of bullets that missed the target by Gun C is 6.25% less than the number of bullets fired by Gun A. Time gap between the firing of two bullets is 5 seconds, 3 seconds and 7 seconds for Gun A, Gun B and Gun C respectively.

If Gun C fired continuously from 12:30 pm to 12:34 pm and not any time before that, then how many bullets were left to be fired by Gun C after this period of shooting?

Gun B:
Total number of bullets fired = 900
Number of bullets that hit the target = 900 × 33.33% = 300
Number of bullets that missed the target = 900 – 300 = 600
Gun A:
Number of bullets that hit the target = 300 × 80% = 240
Total number of bullets fired =240/30 x 100 = 800
Number of bullets missed the target = 800 – 240 = 560
Gun C:
Number of bullets missed the target = 800 × (100 – 6.25)% = 750
Number of bullets hit the target = 450
Total number of bullets fired = 750 + 450 = 1200

The bullets fired by Gun C would make an Arithmetic progression with first term 0(for bullet fired at 12:30 pm) and the common difference would be 7 for rest of the terms.
As, the number of seconds from 12:30 pm to 12:34 pm is 240, the last term of the AP would be 238.(largest multiple of 7 less than 240)
AP : 0, 7, 14…….238

 Number of bullets fired by Gun C from 12.30 pm to 12.34 pm
Remaining number of bullets in Gun C = 1200 – 35 = 1165
Hence, option A is correct.

By: Munesh Kumari