The amount with S in his wallet is less than Rs 1000 and the number of notes of each denomination wi...........

Quantitative Aptitude(IBPS CL) Data Table

Direction: Study the following information carefully and answer the questions that follow.
Four people(P, Q, R, S) have certain amount of money in their wallets. The currency notes in the wallet of the four people were in only 3 denominations.(D-I, D-II, D-III)
The table given below shows the total amount that the four people have and the amount of the three different denominations for the four people.
The amount with S is missing from the table.

It is also known that each of the 4 people had the same number of currency notes for each of the denominations i. e. For person P: Number of notes of denomination D-I = Number of notes of denomination D-II = Number of notes of denomination D-III. This holds true for all the 4 people.

The amount with S in his wallet is less than Rs. 1000 and the number of notes of each denomination with S lies between 20 and 30 and is a prime number. Find the total number of currency notes with S.

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Explanation:

Let the number of currency notes of each denomination with P be x.
According to the data provided in the question, we get
50x + 20x + 10x = 1120
⇒ 80x = 1120
⇒ x = 14
The number of currency notes of each denominations that with P = 14
Let the number of currency notes of each denomination with Q be y.
According to the data provided in the question, we get
100y + 20y + 5y = 3250
⇒ 125y = 3250
⇒ y = 26
The number of currency notes of each denominations with Q = 26
Let the number of currency notes of each denomination with R be z.
According to the data provided in the question, we get
200z + 50z + 20z = 5400
⇒ 270z = 5400
⇒ z = 20
The number of currency notes of each denominations with R = 20
Let the number of currency notes of each denomination with S be s.
Total amount that S has = 20s + 10s + 5s = Rs. 35s
The prime numbers that lies between 20 to 30 are 23 and 29.
Case I: Number of currency notes of each denomination with T = 29
According to the data provided in the question, we get
Total amount with S = 35 × 29 = Rs. 1015
This is not possible because the amount should be less than Rs. 1000.
Case II: Number of currency notes of each denomination with T = 23
According to the data provided in the question, we get
Total amount that S has = 35 × 23 = Rs. 805
So, the total number notes of all denominations with S = 23 × 3 = 69
Hence, option C is correct.