T has currency notes of three denominations Rs 500 Rs 20 and Rs 10 If T has total amount of Rs 3710 ...........

Quantitative Aptitude(IBPS CL) Data Table

Direction: Study the following information carefully and answer the questions that follow.
Four people(P, Q, R, S) have certain amount of money in their wallets. The currency notes in the wallet of the four people were in only 3 denominations.(D-I, D-II, D-III)
The table given below shows the total amount that the four people have and the amount of the three different denominations for the four people.
The amount with S is missing from the table.

It is also known that each of the 4 people had the same number of currency notes for each of the denominations i. e. For person P: Number of notes of denomination D-I = Number of notes of denomination D-II = Number of notes of denomination D-III. This holds true for all the 4 people.

T has currency notes of three denominations - Rs. 500, Rs. 20 and Rs. 10 . If T has total amount of Rs. 3710 in his wallet, then the number of currency notes of each denomination that T has is how much less than the number of currency notes that P has? All the above given conditions apply to T as well.

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Explanation:

Let the number of currency notes of each denomination with P be x.
According to the data provided in the question, we get
50x + 20x + 10x = 1120
⇒ 80x = 1120
⇒ x = 14
The number of currency notes of each denominations that with P = 14
Let the number of currency notes of each denomination with Q be y.
According to the data provided in the question, we get
100y + 20y + 5y = 3250
⇒ 125y = 3250
⇒ y = 26
The number of currency notes of each denominations with Q = 26
Let the number of currency notes of each denomination with R be z.
According to the data provided in the question, we get
200z + 50z + 20z = 5400
⇒ 270z = 5400
⇒ z = 20
The number of currency notes of each denominations with R = 20
Let the number of currency notes of each denomination with S be s.
Total amount that S has = 20s + 10s + 5s = Rs. 35s
Let the number of currency notes of each denomination with T be a.
According to the data provided in the question, we get
500a + 20a + 10a = 3710
⇒ 530a = 3710
⇒ a = 7
The number notes of each denomination with T = 7
Required answer = 14 – 7 = 7
Hence, option D is correct.