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A container contains 765 litres mixture of milk and water in the ratio of 10 : 7 respectively. If 20% mixture was taken out and 2X litre milk and (3X – 32) litre water is added in the remaining mixture, then the ratio of the milk to water in the final mixture becomes 6 : 5. What is the difference between the quantity of milk and water in the final mixture?
The quantity of water in the mixture =765/17 x10 = 450 litres
The quantity of milk in the mixture = 765/17 x 7= 315 litres
The quantity of the mixture that is taken out = 765 × 0.20 = 153 litres
According to the data provided in the question, we get:
⇒ 5(360 + 2X) = 6(220 + 3X)
⇒ 1800 + 10X = 1320 + 18X
⇒ 8X = 480
⇒ X = 60
Quantity of milk in the final mixture = 450 – 90 + 120 = 480 litres
Quantity of water in the final mixture = 315 – 63 + 148 = 400 litres
Required difference = 480 – 400 = 80 litres
By: Munesh Kumari ProfileResourcesReport error
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