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What is the escape velocity of a planet having mass 6 times and radius 2 times as that of earth?
3 ve
√3 ve
√2 ve
2 ve
Option 2nd is correct.
The escape velocity vesc is expressed as vesc = Square root of√2GMr,where G is the gravitational constant, M is the mass of the attracting mass, and r is the distance from the centre of that mass. So when M=6times and R=2R, then ve becomes √3 ve.
By: Gagandeep Singh ProfileResourcesReport error
ANKUR KUMAR VERMA
WHAT IS THE SHORT FORM OF ESCAPE VELOCITY (EV(OR)VE).PLEASE EXPLANATION THE ANSWER PROPERLY.I HAVE NOTE SOLVE THIS QUESTION BY GIVEN FORMULA.
Rectified, Please check out explanation part
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