send mail to firstname.lastname@example.org mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
Please verify your mobile number
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Refer & Earn
My Abhipedia Earning
Kindly Login to view your earning
A far-sighted person has a near point at 100 cm. What must be the power of the correcting lens?
– 0.8 D
– 3.0 D
+ 0. 8 D
+ 3.0 D
Given near point = 100 cm. Power , P=1/f or 100/f D=100*3/100
By: Abhipedia ProfileResourcesReport error
Access to prime resources