Match List I Oxidation number with List II The element and select the correct answer using the codes...........

General Science (Easy) Chemistry

Match List-I (Oxidation number) with List II (The element) and select the correct answer using the codes given below the lists :

List-I (Oxidation number)	List-II (The elements)
A. 2	1. Oxidation number of Mn in MnO₂
B. 3	2. Oxidation number of S in H₂S₂O₇
C. 4	3. Oxidation number of Ca in CaO
D. 6	4. Oxidation number of Al in NaAlH₄

A-3; B-4; C-1; D-2

A-4; B-3; C-1;D-2

A-3; B-4; C-2; D-1

A-4; B-3; C-2;D-1

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Explanation:

A-3; B-4; C-1; D-2

The oxidation number characterizes the oxidation state of an element in a compound. It is a full number, positive or negative, which indicates the amount of electron loss or gain by this element in the given compound, with respect to the neutral atom.

Oxidation number of calcium is 2 in calcium oxide (CaO).
Oxidation number of Aluminium is +3 in Sodium aluminium hydride (NaAlH4) is a chemical compound used as a reducing agent.
Oxidation number of manganese is 4 in Manganese dioxide (MnO2).
Oxidation number of sulphur is 6 in Pyrosulfuric Acid (H2S2O7).

Hence option 1st is correct.