Explanation:

To find the volume occupied by 5.6 grams of nitrogen at normal temperature and pressure, follow these steps:

- Molecular weight of nitrogen (N2): 14 x 2 = 28 grams/mole.

- Calculate moles of nitrogen: 5.6 grams / 28 grams per mole = 0.2 moles.

- Volume occupied by 1 mole of gas: 22.4 litres (at normal temperature and pressure).

- Volume occupied by 0.2 moles: 0.2 x 22.4 litres = 4.48 litres.

Given the options, the correct answer is:

- Option 1: 2.24 litres – Incorrect, as it’s too low.

- Option 2: 4.48 litres – Correct volume.

- Option 3: 11.2 litres – Too high, equivalent to 0.5 moles of gas.

- Option 4: 22.4 litres – It's for 1 mole, not applicable here.

Option 2: 4.48 litres is correct.