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There are four identically sized and shaped balls in a box, with only its top open. Each ball is of a different colour, these being Green, Red, White and Blue, with only one ball of each colour. Without looking into the box, one ball is randomly picked out and its colour is noted; then it is returned to the box. What are the chances that, in two successive draws, one may get the white ball and the red ball in whichever order?
1/16
1/8
1/4
1/2
Let's find the probability of drawing the white ball and the red ball in two successive draws, in any order:
- First draw possibilities:
- White followed by Red
- Red followed by White
- Probability for White followed by Red:
- Probability of picking White first = 1/4
- Probability of picking Red second = 1/4
- Combined for this order = (1/4) × (1/4) = 1/16
- Probability for Red followed by White:
- Probability of picking Red first = 1/4
- Probability of picking White second = 1/4
- Total probability: 1/16 + 1/16 = 1/8
The correct option is:
Option 2: 1/8
By: Udit Singla ProfileResourcesReport error
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