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Container X contains a mixture of oil and water in the ratio 1 : 3, whereas container Y contains a mixture of oil and water in the ratio 2: 3. If 2 litres of liquid from container X and 5 litres of liquid from container Y are mixed together in container Z that initially contains 1 litre of pure oil, then what is the percentage of oil in container Z ?
41.25
42.75
43.75
44.25
- First, calculate the amount of oil in each container before mixing:
- Container X: Mixture ratio is 1:3, thus 1/4 is oil. So, 2 liters from X has 0.5 liters of oil.
- Container Y: Mixture ratio is 2:3, thus 2/5 is oil. So, 5 liters from Y has 2 liters of oil.
- Calculate total oil in container Z:
- Initial oil in Z: 1 liter
- Oil from X: 0.5 liters
- Oil from Y: 2 liters
- Total oil: 1 + 0.5 + 2 = 3.5 liters
- Total liquid in Z: 1 (initial oil) + 2 (from X) + 5 (from Y) = 8 liters
- Calculate the percentage of oil in Z:
- Oil percentage = (3.5 / 8) x 100 = 43.75%
- Correct Option: 3 - 43.75
By: Babita ProfileResourcesReport error
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