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An incandescent bulb rated as 100 W at 110 V is connected to a 220 V power supply. The power that dissipates in the bulb would be :

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EPFO EO AO 2023

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50 W

100 W

200 W

400 W

Explanation:

- The power dissipated in a resistive load like a bulb is given by the formula P = V²/R. You need to find the resistance (R) first using the rated values.

- For the 100 W at 110 V bulb, R = 110²/100 = 121 Omega

- Now connect it to 220 V: P = 220²/121 = 400 W

- When the voltage is doubled, power dissipation quadruples due to the squared relationship in the formula.

- Correct Answer: 400 W

By: Parvesh Mehta

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