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A bus passes two persons moving in the direction of the moving bus at a speed of 3 km/h and 5 km/h, respectively. The bus passes the first person in 10s and the second person in 11s. The speed of the bus is :
25 km/h
24 km/h
27 km/h
28 km/h
- Let the length of the bus = L meters
- Relative speed when passing first person = (Bus speed - 3) km/h
- Time taken = 10 seconds = 10/3600 hours
- So, L = (Bus speed - 3) × (10/3600) × 1000 meters
- Similarly, for the second person: Relative speed = (Bus speed - 5) km/h; Time = 11 s
- L = (Bus speed - 5) × (11/3600) × 1000 meters
- Equate both: (Bus speed - 3) × 10 = (Bus speed - 5) × 11
- Solving: 10x - 30 = 11x - 55 ? x = 25 km/h
- Option 1: 25 km/h — Correct
- Option 2: 24 km/h — Incorrect
- Option 3: 27 km/h — Incorrect
- Option 4: 28 km/h — Incorrect
Correct Answer: 25 km/h
By: Parvesh Mehta ProfileResourcesReport error
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