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Two pipes A and B can fill 20 gallons and 30 gallons of water in one hour respectively and the third pipe C can empty ‘x’ gallons of water in an hour. If all the three are opened together, the tank gets filled in 15 hours, and when pipe A and B are opened together the tank gets filled in 12 hours, then find how much gallons of water are drained by pipe C in an hour ?
15
20
30
10
Gallons of water filled by pipe A and B in one hour = 20 + 30 = 50 Capacity of the tank = 50 × 12 = 600 gallon Now three pipes together, ⇒ (20 + 30 – x) × 15 = 600 ⇒ 300 + 450 – 15x = 600 ⇒ 15x = 750 – 600 ⇒ X =150/15 = 10 gallons.
By: sunny bhonsle ProfileResourcesReport error
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