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X and Y run a 3 km race along a circular course of length 300m. Their speeds are in the ratio 3:2. If they start together in the same direction, how many times would the first one pass the other (the start-off is not counted as passing)?
The faster runner will cross the slower one when he covers an extra 300 m.
Let their speeds be 3 m/sec and 2 m/sec.
So, their relative speed = 3 – 2 = 1 m/sec
So, the time taken by the faster runner to cross the slower one = Distance/Relative Speed = 300/1 = 300 seconds
It basically means that the faster runner will cross the slower one every 300 seconds, or 5 minutes.
Now, the time taken for the faster racer to complete the entire race = Total Distance/Speed = 3000/3 = 1000 seconds.
So, the faster racer will cross the slower one 3 times during the entire race – after 300 seconds, 600 seconds, and 900 seconds.
By: Munesh Kumari ProfileResourcesReport error
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