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There are two containers X and X contains 100 ml of milk and Y contains 100 ml of water. 20 ml of milk from X is transferred to Y. After mixing well, 20 ml of the mixture in Y is transferred back to X. If m denotes the proportion of milk in X and n denotes the proportion of water in Y, then which one of the following is correct?
m=n
m> n
m<n
Cannot be determined due to insufficient data
Container X contains 100 ml of milk and container Y contains 100 ml of water. If 20 ml of milk transferred from container X to container Y, then: Amount of milk left in container X = 100 – 20 = 80 ml Amount of solution in container Y becomes = 100 ml water + 20 ml milk = 120 ml Ratio of milk and water in container Y = 20 : 100 = 1 : 5 Amount of milk in 20 ml solution of container Y = (1/6) × 20 = 3.33 ml Amount of water in 20 ml solution = 20 – 3.33 = 16.67 ml If 20 ml of this solution is transferred from container Y to container X, then: Amount of solution in container X becomes = (80 + 3.33), i.e. 83.33 ml milk + 16.67 ml water Amount of solution in container Y becomes = (100 – 16.67), i.e. 83.33 ml water + (20 – 3.33), i.e. 16.67 ml milk As per the question, m denotes the proportion of milk in X, and n denotes the proportion of water in Y. So, m = 83.33 ml and n = 83.33 ml Thus, m = n
By: Munesh Kumari ProfileResourcesReport error
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