Let p be a two digit number and q be the number consisting of same digits written in reverse order I...........

Explanation:

p is a two-digit number, and q is the number consisting of the same digits in the reverse order.
It’s given that, p × q = 2430
The last digit of the product is 0, which indicates that one two of the digits must be 5.
Let the remaining digit be x.
So, p = x5 = x × 10 + 5 = 10x + 5
Reverse number, q = 5x = 5 × 10 + x = 50 + x
According to the question,
(10x + 5) × (50 + x) = 2430
Or 500x + 10x2 + 250 + 5x = 2430
Or 10x2 + 505x – 2180 = 0
Or 2x2 + 101x – 436 = 0
Or x(2x + 109) – 4(2x + 109) = 0
Or (x – 4)(2x + 109) = 0
Or x = 4, or –109/2 (can be neglected)
So, x = 4
Therefore, p = x5 = 45
And q = 54
Required difference = 54 – 45 = 9