How many 3 digit natural numbers without repetition of digits are there such that each digit is odd ...........

Math and Mental Ability Permutation & Combination

How many 3-digit natural numbers (without repetition of digits) are there such that each digit is odd and the number is divisible by 5?

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Explanation:

We need to find three-digit numbers in which:
* All digits are different, and all digits are odd. So, the three digits must be from amongst 1, 3, 5, 7, and 9.
* The number is divisible by 5, i.e. the units digit is 5.
The number of ways we can fill the first two digits from amongst 4 distinct digits = 4 × 3 = 12.