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Consider all 3-digit numbers (without repetition of digits) obtained using three non-zero digits which are multiples of 3. Let S be their sum.
Which of the following is/are correct?
1. S is always divisible by 74.
2. S is always divisible by 9.
Select the correct answer using the code given below:
1 only
2 only
Both 1 and 2
Neither 1 nor 2
Three non-zero digits which are multiples of 3 are: 3, 6, and 9. Using these 3 digits, we can make 3!, i.e. 6 three-digit numbers. So their sum, S = 369 + 396 + 639 + 693 + 936 + 963 = 3996 We can see that, S is divisible by both 74 and 9.
By: Munesh Kumari ProfileResourcesReport error
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