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In adult Population or a city, 40 men and 30% women are married. What is the percentage of married adult population if no man marries more than one woman and no woman marries more than one man; and there are no widows and widowers?
34%
35%
Sol. Ans.(c).
Traditional Method - Let total no. of men = X and Total population be 100.
Total women = (100 − X)
Married men = 40 X/100 …(i) and Married women = (100 − X) × 30/100 …(ii)
But, No. of married men = No. of married women. (as per conditions given)
So, from (i) and (ii) X = 300/7
So, married Men = 300/7 X 40/100 = 120/7 and Married women = 120/7.
Total married population = Men + Women = 240/7
Required percentage = 240/7 % = 342/7 %. So the correct option is (c).
Alternative method: No man marries more than one woman and no woman marries more than one man. It means the Number of married men = Number of married women = 120 (let). Married adult population = 240.
Number of men = 120×100/40 = 300 and Number of women 120 × 100/30 = 400. So, total population = 300 + 400 = 700.
Required percentage 240×100/700 = = 240/7 % = 342/7 %
By: Brijesh Kumar ProfileResourcesReport error
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