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Rohan started practicing maths from 3rd June. He could solve only 3 problems on the first day. However, he increased his speed such that he solved 6 problems on the second day, 9 on the third, and so on. If he continued this trend throughout June, how many problems did he solve on 25th June of the same year?
57
66
63
None of these
- Rohan started on 3rd June, solving 3 problems on the first day.
- Each day he increases the number of problems by 3 (3, 6, 9,...).
- This pattern forms an arithmetic sequence: \(a_n = 3n\), where \(n\) is the day since he started.
- By 25th June, he would have practiced for 23 days since 3rd June.
- Using the sequence \(a_n = 3n\), on the 23rd day, he solves \(3 \times 23 = 69\) problems.
- None of the given options (57, 66, 63) are correct.
So, the correct answer is option:4- None of these.
Your answer is right
By: Sandeep Dubey ProfileResourcesReport error
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