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Two inlet pipes A and B can fill a tank in 10 minutes and 25 minutes respectively. Both pipes are simultaneously opened but pipe A is closed after 5 minutes. What is the time now required to fill the tank?
9.2 minutes
7.5 minutes
13.4 minutes
11 minutes
- Pipe A can fill the entire tank in 10 minutes, so in 1 minute, it fills 1/10 of the tank.
- Pipe B can fill the entire tank in 25 minutes, so in 1 minute, it fills 1/25 of the tank.
- In the first 5 minutes, both pipes fill together.
- Together, in one minute, they fill \( \frac{1}{10} + \frac{1}{25} = \frac{5}{50} + \frac{2}{50} = \frac{7}{50} \) of the tank.
- In 5 minutes, they fill \( 5 \times \frac{7}{50} = \frac{35}{50} = \frac{7}{10} \) of the tank.
- Now, only \(\frac{3}{10}\) of the tank is left to be filled by Pipe B.
- Pipe B fills \(\frac{1}{25}\) of the tank in one minute.
- To fill \(\frac{3}{10}\) of the tank, it takes \(\frac{3}{10} \div \frac{1}{25} = \frac{3}{10} \times 25 = 7.5\) minutes.
- Option 2: 7.5 minutes is correct.
By: Sandeep Dubey ProfileResourcesReport error
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