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Find the smallest digit that will leave same remainder 4 in each case when divided by 12, 15, 20, and 54.
454
540
544
450
Take LCM of 12, 15, 20, and 54. It will be = 540.
ATQ, the remainder in each case = 4.
Hence, the required number = 540+4 = 544.
By: Parvesh Mehta ProfileResourcesReport error
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