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Mr. Kumar drives to work at an average speed of 48km/hr. The time taken to cover the first 60% of the distance is 10 minutes more than the time taken to cover the remaining distance. How far is his office?
30km
40km
45km
48km
Let the distance be N. First 60% distance is covered in 10 more minutes more time than that of the rest 40% distance So, 0.6 x N distance is covered in 10 more minutes more than that of the rest 0.4 x N distance Which means 0.2 x N is covered in 10 minutes i.e., 1/6 hr Hence, Average speed = distance/time = 0.2 x N /(1/6) = 48 => x = 48/6 x 0.2 =40 km
By: Parvesh Mehta ProfileResourcesReport error
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