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In a certain code ORBITAL is written as CSPHMBU. How is* CHARGER written in that code?
BIDQSFH
BIDSSFH
BIDQQDF
None of these
- To solve the code, analyze the pattern in the transformation from ORBITAL to CSPHMBU.
- O?C: This is a shift of 2 letters forward in the alphabet.
- R?S: This is a shift of 1 letter forward.
- B?P: This is a shift of 14 letters forward.
- I?H: This is a shift of 1 letter backward.
- T?M: This is a shift of 7 letters backward.
- A?B: This is a shift of 1 letter forward.
- L?U: This is a shift of 9 letters forward.
- Now, apply the same shifts to CHARGER:
- C?B: 1 letter backward.
- H?I: 1 letter forward.
- A?D: 3 letters forward.
- R?Q: 1 letter backward.
- G?S: 12 letters forward.
- E?F: 1 letter forward.
- R?H: 10 letters forward.
- Therefore, CHARGER is written as BIDQSFH.
- Options:
- Option 1: BIDQSFH: Matches the derived code.
- Option 2: BIDSSFH: Incorrect sequence.
- Option 3: BIDQQDF: Incorrect sequence.
- Option 4: None of these: Not applicable.
- Answer: Option 1: BIDQSFH
-
By: Parvesh Mehta ProfileResourcesReport error
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