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Ramesh, Mahesh and Suresh throw a dice in succession till one gets a ‘six’ and wins the game. Then the probability of Ramesh’s winning is:
25/91
36/91
31/90
None of these
Solution: P (throwing a ‘six’ in a single throw) = 1/6 And P (not throwing a six in a single throw) = 5/6 Suppose that Ramesh has the first throw, then Ramesh wins at 1st, 4th, 7th, 10th, ……… throw and all these ways of winning are mutually exclusive.
By: Narinder Singh ProfileResourcesReport error
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