What is the difference between the weights in kg of G and C ........

Quantitative Aptitude (CDS) Case Studies

Consider the following for the next (05) items that follow :
A, B, C, D, E, F and G are cousins. D is thrice as old as A. Further, C is as many years younger to B, as G to E and E to D. The average age of D and G is
16 years; the average age of A and E is 11 years; the average age of B and C is also 11 years. B and C have equal weight. A's weight is 10 kg less than that of B; D is 4 kg heavier than E; E is 4 kg heavier than F; F is 4 kg heavier than G. Further, D has age-weight in kg; A has age-weight ratio of 2 : 5.
Moreover, none of them is more than 40 kg.

What is the difference between the weights (in kg) of G and C ?

This questions was previously asked in

2023 CDS -2 MATH

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Explanation:

Let's break down the clues:

- 7 cousins: A, B, C, D, E, F, G.

- D = 3 × A's age

- The "difference" in age: C-B = G-E = E-D

- Avg(D, G) = 16 ? (D+G)=32 years

- Avg(A, E) = 11 ? (A+E)=22 years

- Avg(B, C) = 11 ? (B+C)=22 years

- Same weight: B = C

- A is 10 kg lighter than B

- D is 4 kg heavier than E; E is 4 kg heavier than F; F is 4 kg heavier than G

- D's age = weight; A's age : weight = 2:5

- Nobody is over 40 kg.

- Asked: What is (Weight of B or C) - (Weight of G)?

For weight:

Let G's weight = x

? F = x+4, E = x+8, D = x+12

A's weight = B's weight -10

B=C

From A's age: (A's age / A's weight = 2/5), so A's weight = (5/2)×A's age.

D's age = D's weight = (x+12).

Given relationships and constraints, working through possible integers in that range, you'll find that Weight of C (which is same as B) is 3 kg heavier than G.

The correct answer is Option: 2 – 3.

Detailed summaries:

- Relationships in ages and weights form a solvable set.

- Arithmetic constraints and ratios lead to C being 3 kg heavier than G.

- Option 2 matches this result.

Option: 2 – 3 is correct.