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The corners of an equilateral triangular plate were cut in such a manner that it forms a regular hexagonal plate. What is the ratio of the area of the triangular plate to the area of the hexagonal plate ?
2 : 1
3 : 2
4 : 3
5 : 3
Here's the solution explained step by step in clear points:
- An equilateral triangle can be cut at its corners (each cut is parallel to the opposite side) to form a regular hexagon.
- Let the side of the original triangle be \(a\).
- The largest hexagon inscribed in an equilateral triangle has each of its sides one-third the side of the triangle.
- Area of the equilateral triangle: \(\frac{\sqrt{3}}{4}a^2\)
- Side of the hexagon: Let’s call it \(x\). \(x = \frac{a}{3}\)
- Area of regular hexagon:
$$6 \times \frac{\sqrt{3}}{4}x^2 = \frac{3\sqrt{3}}{2}x^2$$
Substitute \(x = \frac{a}{3}\):
$$
= \frac{3\sqrt{3}}{2}\left(\frac{a^2}{9}\right) = \frac{\sqrt{3}}{6}a^2
- Ratio of triangle area to hexagon area:
\frac{\frac{\sqrt{3}}{4}a^2}{\frac{\sqrt{3}}{6}a^2} = \frac{6}{4} = \frac{3}{2}
- Among the options, Option 2: 3:2 matches.
Correct Answer: Option 2: 3 : 2
By: Parvesh Mehta ProfileResourcesReport error
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