send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
The upper part of a tower is broken by the wind makes an angle of 45 degrees with the ground and the distance from the root to the point where the top of the tower touches the ground is 10m .what was the height of the tower?
30+10√2 m
10√2-10 m
20+10√2 m
10+10√2 m
Let Tower height after the break is h metre
Base to touced point is 10m
tan 45 ° =h/10
1= h /10
h =10 m
diagonal =(10² +10²)^½
=√ (200)
=10√2 m
h1=h+diagonal value
=10+10√2 m
By: bhavesh kumar singh ProfileResourcesReport error
Access to prime resources
New Courses