In tossing two coins at a time what is the probability of getting at most one tail ........

Quantitative Aptitude (CDS) Probability

In tossing two coins at a time, what is the probability of getting at most one tail?

Possible outcomes are

{ (H,H) ,(H,T) ,(T,H) ,(T,T) }

Let E be the event of getting one tail.

E={ (H,T),(T,H) }

Let F be the event of getting no tail.

F={ (H,H) }

Total number of outcomes =4

Therefore P(E)=2/4=1/2

and P(F)=¼

Thus required probability=P(E ) +P(F)

=½+¼

=3/4

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