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Find the no. of digits in 2^15 (Given that log 2 = 0·3010).
6
5
3
10
Applying the rule, we have the required answer = (Integral part of 15 log 2) + 1
= (15 × 0·3010) + 1
= [4.515 + 1]
= 4 + 1= 5
By: bhavesh kumar singh ProfileResourcesReport error
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