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Two small squares on a chessboard are chosen at random. Find the probability that they have no common side?
1/18
17/18
1/17
1/19
The common side could be horizontal or vertical. The number of ways that they have a common side = 8×7 + 8×7 Total number of ways of choosing two squares = 64C2 = 64× 63 /2 Thus , P ( they have a common side) = 2×8×7×2/64×63 = 1/18 Therefore , P ( they have no common side ) = 1 – 1/18 = 17/18
By: bhavesh kumar singh ProfileResourcesReport error
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