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. A rectangle of 64×42 dimension, there is 5m wide two-path middle of rectangle one is parallel to the length and the other is parallel to breadth. Find the area of path?
500 cm^2
505 cm^2
400 cm^2
510 cm^2
Length of rectangle=64 cm
Width=42 cm
Area of path parallel to length=5×64
=320 cm^2
Area of path parallel towidth=42×5=210 cm^2
Common area=25 cm^2
320+210-25=505 cm^2
By: bhavesh kumar singh ProfileResourcesReport error
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