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A tank has leakage in its bottom, drain the water of the tank in 15 hours. Two tap A and B can fill the tank in 9 and 12 hours. If tank A and B fill the tank together for 2/3 of the tank. Remaining tank filled by only B tap. Total time to fill the tank?
580/23 hours
580 hours
290/23 hours
17 hours
Let up to 2/3 it fill in t time t(1/9 + 1/12 -1/15) =2/3 t(20+15-12) /180 =2/3 t=120/23 t1(1/12 -15) =1/3 t1 =20 Total time =t+t1 =20+120/23 =580/23 hours
By: bhavesh kumar singh ProfileResourcesReport error
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