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Out of 9 men & 6 women, a committee of five persons is to be selected such that men are in the majority . find the number of such committees.
2142
2400
2428
2200
majority possibilities = (3M , 2W) or (4M ,1W) or (5M , 0W) No. of such committee = 9C3 × 6C2 + 9C4 × 6C1 + 95 × 6C0 = 1260 + 756 + 126 = 2142
By: bhavesh kumar singh ProfileResourcesReport error
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