Explanation:

condition for real and unequal roots D > 0
b² - 4ac > 0
from first equation 4c² - 8ab > 0
from equation second D = b² - 4ac
D =4 (a+b )² -4 (a²+b²+c²) 
On solving we get D = -(4c² - 8ab)
HENCE , D < 0
Roots are non real