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Given that a,b,c are real and distinct number then find the nature of roots of this equation (a+c-b) x² + 2cx + (b + c –a ) = 0 .
real and equal
real and unequal
imaginary roots
can’t find
Formula D = b² - 4ac where from given equation A → ( a+c-b) B → 2c C → ( b + c –a ) Put these value in above equation and on solving it we get finally D = 4 ( a- b )² a, b, c distinct . hence D > O so roots are real and unequal
By: bhavesh kumar singh ProfileResourcesReport error
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